Sulphuric Acid 0.1N

Description

Product Technical bulletin

Sulphuric acid Equivalent weight = 49 



Normality you can decided i.e. you prepare 0.1N 



water 1 lit of water 



First = Eq.wt x 0.1 N x 1 lit of water 



= 49 x 0.1 x 1= 4.9 g 



Sulphuric acid you only measure only ml 



so you put = gram / (Specific Gravity x Percentage Concentration) 



= 49 / (1.83×97) 

= 49/177.51 

= 2.76 ml of Sulphuric acid you take one litre of water

Product label
This range of standardised solutions provides a convienient method for accurate volumetric analysis.